An electrolyte solution has an average current density of 111 ampere per square decimeter \left( \dfrac{\text{A}}{\text{dm}^2}\right)( dm 2A )left parenthesis, start fraction, start text, A, end text, divided by, start text, d, m, end text, squared, end fraction, right parenthesis.What is the current density of the solution in \dfrac{\text{A}}{\text{m}^2} m 2A start fraction, start text, A, end text, divided by, start text, m, end text, squared, end fraction?
Accepted Solution
A:
Answer:The current density of the solution in [tex]m^2[/tex] is [tex]11100A/m^2[/tex]Step-by-step explanation:One square decimeter is equal to 0.01 square meter, Thus the current density in square meters is [tex]\frac{111A}{dm^2} =\frac{111A}{0.01m^2} =\frac{111}{0.01}*\frac{A}{m^2}=\boxed{11100A/m^2}[/tex]11100 Amperes per square meter.